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(3x/x+2)+(6/x)=(12/x^2-2x)
We move all terms to the left:
(3x/x+2)+(6/x)-((12/x^2-2x))=0
Domain of the equation: x+2)!=0
x∈R
Domain of the equation: x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: x^2-2x))!=0We add all the numbers together, and all the variables
x∈R
(3x/x+2)+(+6/x)-((12/x^2-2x))=0
We get rid of parentheses
3x/x+6/x-((12/x^2-2x))+2=0
We calculate fractions
We do not support expression: x^3
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